#include <iostream>

using namespace std;

typedef long long ll;

inline ll C(ll n, ll k) {
    //cout<<n<<' '<<k<<' '<<(n) / (k + 1)<<' '<<n / k<<endl;
    return n / k - (n) / (k + 1);
}

int main() {
    ll n, m;
    ll sol = 0;
    ll k, x;

    cin>>n>>m;
    --n;

    for (k = 1; k * k <= n; ++k) {
        sol -= k * C(n, k);
    }
    x = k - 1;
    for (k = 1; (n / k) > x; ++k) {
        sol -= n / k;
    }
    //if (k * k == n) {
    //    sol -= n / k;
    //}
    //cout<<sol<<endl;
    for (k = 1; k * k <= m; ++k) {
        sol += k * C(m, k);
    }
    x = k - 1;
    for (k = 1; (m / k) > x; ++k) {
        sol += m / k;
    }
    //if (k * k == m) {
    //    sol += m / k;
    //}

    cout<<sol<<'\n';
}