#include <iostream>
#include <cstdlib>
#include <algorithm>
#include <vector>

using namespace std;

struct
elem{
	unsigned long int val;
	unsigned long int steps;
	unsigned long int eval;
	bool operator<(const elem& e)const{
		return val < e.val;
	}
	bool operator==(const elem& e)const{
		return val == e.val;
	}
};

int
main(){
	int a, b;
	cin >> a >> b;
	int steps = 37;
	
	elem* v = new elem[5000007];//vector<elem> v(100000000);
	
	while(a != 0 && b != 0){
	steps++;
	unsigned long int c = min(a, b);
	
	
		
	int counter = 0;
	v[c].val = 0;
	v[c].steps = steps;
	int hash = 0;
	while(c != 1){
		if(c%2 == 0){
			c /= 2;
		}
		else{
			c = 3*c + 1;
		}
		++counter;
		
	    hash =0;
		while (v[(c%5000007 + hash*(c%4998231))%5000007].steps == steps){
		   hash ++;
		   //if (hash)
		}
		v[(c%5000007 + hash*(c%4998231))%5000007].val = counter;
		v[(c%5000007 + hash*(c%4998231))%5000007].steps = steps;
		v[(c%5000007 + hash*(c%4998231))%5000007].eval = c;
	}
	
	//sort(v, &v[100000000]);
	
	c = max(a, b);
	bool cond = true;
	counter = 0;
	
	
	while(c != 1 && cond){

		elem e;
		e.val = c;
		//vector<elem>::iterator low = lower_bound(v.begin(), v.end(), e);
		
		hash =0;
		while (v[(c%5000007 + hash*(c%4998231))%5000007].steps == steps){
		
		
		    if (v[(c%5000007 + hash*(c%4998231))%5000007].eval == c){
		    break;
		    
		    }
		    hash ++;
		
		}
		
		if(v[(c%5000007 + hash*(c%4998231))%5000007].steps == steps){
			if( a > b ){
				cout << a << " needs " << counter << " steps, " << b << " needs " << v[(c%5000007 + hash*(c%4998231))%5000007].val << " steps, they meet at " << c << endl;
			}
			else{
				cout << a << " needs " << v[(c%5000007 + hash*(c%4998231))%5000007].val << " steps, " << b << " needs " << counter << " steps, they meet at " << c << endl;
			}
			break;
		}
		
		if(c%2 == 0){
			c /= 2;
		}
		else{
			c = 3*c + 1;
		}
		++counter;
		
		if (c==1){
		
		if( a > b ){
				cout << a << " needs " << counter << " steps, " << b << " needs 0 steps, they meet at " << c << endl;

			} else {
			    cout << a << " needs 0 steps, " << b << " needs " << counter << " steps, they meet at " << c << endl;
			}
			
			
			break;
		
		}
	}
	
	
	if (a==1 && b == 1){
	cout << "1 needs 0 steps, 1 needs 0 steps, they meet at 1"<< endl;
	}
	cin >> a >> b;
	}
	
	return 0;
}